Đáp án:
(y+2)x+1= y^2
=> xy+2x+1=y ²
=> x ²/4+2x+16-15=y ²-xy+x ²/4
=> (x/2+4) ²-15=(y-x/2) ²
=> (x-y+4)(y+4)=15
x,y nguyên => x-y+4, y+4 nguyên
=> y+4 ∈{-15,-5,-3,-1,1,3,5,15}
=> y ∈{-19, - 9,-7,-5,-3,-1,1,11}
y=-19=> x= -24
y=-9=> x=-16
y=-7=> x=-16
y=-5=> x=-10
y=-3=> x=8
y=-1=> x=0
y=1=>x=0
y=11=>x= 8