Đáp án:
` ( 6x +1)^{2020} + (3y+1)^{2020} + |x + y + 2z^2| = 0`
Ta có
` ( 6x +1)^{2020} \ge 0`
` (3y+1)^{2020} \ge 0`
` |x + y + 2z^2| \ge 0`
` =>`
` 6x + 1 = 0 => x = -1/6`
` 3y +1 = 0 => y= -1/3`
` x + y + 2z^2 = 0`
` => -1/6 - 1/3 + 2z^2 = 0`
` => 2z^2 = 1/2`
` => z^2 = 1/4`
` => z = ± 1/2`