Đáp án + Giải thích các bước giải:
`(x-1)/2=(y-2)/3=(z-3)/4`
`to (x-1)/2=(2y-4)/6=(3z-9)/12`
`=(x-1-(2y-4)-(3z-9))/(2-6-12)=(x-1-2y+4-3z+9)/(-16)`
`=((x-2y-3z)-1+4+9)/(-16)=(14+12)/(-16)=-13/8`
`to`
`(x-1)/2=-13/8 to 8.(x-1)=-26 to 8x-8=-26 to 8x=-18 to x=-9/4`
`(y-2)/3=-13/8 to 8.(x-2)=-39 to 8y-16=-39 to 8y=-23 to y=-23/8`
`(z-3)/4=-13/8 to 8.(z-3)=-52 to 8z-24=-52 to 8z=-28 to z=-7/2`
Vậy `(x;y;z)=(-9/4;-23/8;-7/2)`
