a,200-198+196-194+192-190+.....+8-6+4-2
= 2+ 2+....+ 2
= 2. 50
= 100
b, $\dfrac{3^{2}}{8.11}$ +$\dfrac{3^{2}}{11.14}$.....$\dfrac{3^{2}}{2017.2020}$
= 3. ($\dfrac{3}{8.11}$ + $\dfrac{3}{11.14}$ ....$\dfrac{3}{2017.2020}$ )
= $3$.( $\dfrac{1}{8}$ -$\dfrac{1}{11}$ +$\dfrac{1}{11}$ -$\dfrac{1}{14}$ +...+ $\dfrac{1}{2017}$ -$\dfrac{1}{2020}$
= $3$. ($\dfrac{1}{8}$ - $\dfrac{1}{2020}$ )
= $3$. $\dfrac{503}{4040}$
= $\dfrac{1509}{4040}$
c, 1.2.3...9- 1.2.3.4.5....8- 1.2.3...7.$8^{2}$
= 1.2.3...8.9- 1.2.3...8- 1.2.....8.8
= ( 1.2.....8).( 9-8-1)
= 8! .0
= 0
Chúc bạn học tốt!