Câu 2:
$y'=2(x^3-2x^2).(x^3-2x^2)'$
$=2(x^3-2x^2).[(x^3)'-(2x^2)']$
$=2(x^3-2x^2).(3x^2-4x)$
Câu 3:
$y'=(x)'+\Big(\dfrac{1}{x}\Big)'-\Big(\dfrac{2}{x^2}\Big)'$
$=1-\dfrac{(x)'}{x^2}+\dfrac{2(x^2)'}{(x^2)^2}$
$=1-\dfrac{1}{x^2}+\dfrac{4x}{x^4}$
$=1-\dfrac{1}{x^2}+\dfrac{4}{x^3}$