$\frac{25}{1.2.3}+...+$ $\frac{25}{20.21.22}$
$=25.\frac{1}{2}.($ $\frac{1}{1.2}-$ $\frac{1}{2.3}+...+$ $\frac{1}{20.21}-$ $\frac{1}{21.22})$
$=\frac{25}{2}.($ $1-\frac{1}{21.22})$
$=\frac{25}{2}.$ $\frac{461}{462}$
$=\frac{11525}{924}$
*Công thức tổng quát:
$\frac{1}{n(n+1)(n+2)}=$ $\frac{1}{2}.($ $\frac{1}{n(n+1)}-$ $\frac{1}{(n+1)(n+2)})$