a) $(\frac{-1}{3})^{2}$ . (9 - $\frac{1}{3}$)
= $\frac{1}{9}$ . $\frac{26}{3}$
= $\frac{26}{27}$
b) $a^{5}$ . $a^{7}$
= $a^{5+7}$
= $a^{12}$
c) $\frac{8^{14}}{4^{12}}$
= $\frac{(2^{3})^{14}}{(2^{2})^{12}}$
= $\frac{2^{42}}{2^{24}}$
= $2^{42-24}$ = $2^{18}$