Giải thích các bước giải:
a, \(\frac{15}{12} + \frac{5}{3}-\frac{3}{12}-\frac{18}{3}\)
\( =1-\frac{13}{3}=\frac{3-13}{3}=\frac{-10}{3}\)
b,\(\frac{13}{25}-\frac{38}{25}+\frac{6}{41}+\frac{35}{41}-\frac{1}{2}=-1+1-\frac{1}{2}=-\frac{1}{2}\)
c, \(12.(\frac{-2}{3})^{2} +\frac{ 4}{3}=12.\frac{4}{3}.\frac{1}{3}+\frac{4}{3}=\frac{4}{3}(12.\frac{1}{3}+1)=\frac{4}{3}.5=\frac{20}{3}\)
d, \(12,5.\frac{-5}{7}+1,5.\frac{-5}{7}=\frac{-5}{7}(12,5+1,5)=\frac{-5}{7}.14=-10\)