Giải:
\(\dfrac{\left(140\dfrac{7}{3}-138\dfrac{5}{12}\right):18\dfrac{1}{6}}{0,002}\)
\(=\dfrac{\left(140\dfrac{28}{12}-138\dfrac{5}{12}\right):18\dfrac{1}{6}}{0,002}\)
\(=\dfrac{\left(2\dfrac{23}{12}\right):18\dfrac{1}{6}}{0,002}\)
\(=\dfrac{\left(2\dfrac{23}{12}\right):\dfrac{109}{6}}{0,002}\)
\(=\dfrac{\dfrac{57}{12}:\dfrac{218}{12}}{0,002}\)
\(=\dfrac{\dfrac{57}{12}.\dfrac{12}{218}}{0,002}\)
\(=\dfrac{\dfrac{57}{1}.\dfrac{1}{218}}{0,002}\)
\(=\dfrac{\dfrac{57}{218}}{0,002}\)
\(=\dfrac{\dfrac{57}{218}}{\dfrac{2}{1000}}\)
\(=\dfrac{57}{218}:\dfrac{2}{1000}\)
\(=\dfrac{57}{218}:\dfrac{1}{500}\)
\(=\dfrac{57}{218}.\dfrac{500}{1}\)
\(=\dfrac{28500}{218}=\dfrac{14250}{109}\)
vậy=
