Giải thích các bước giải:
$\dfrac{3}{4.5}+\dfrac{3}{5.6}+\dfrac{3}{6.7}...+\dfrac{3}{19.20}$
$= 3.\bigg(\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}...+\dfrac{1}{19.20}\bigg)$
$= 3.\bigg(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+....+\dfrac{1}{19}-\dfrac{1}{20}\bigg)$
$=3.\bigg(\dfrac{1}{4}-\dfrac{1}{20}\bigg) = \dfrac{3}{5}$