Đáp án:
$\begin{array}{l}
a)\sqrt {{{\left( {3 - 2\sqrt 2 } \right)}^2}} + \sqrt {{{\left( {3 + 2\sqrt 2 } \right)}^2}} \\
= 3 - 2\sqrt 2 + 3 + 2\sqrt 2 \\
= 6\\
b)\sqrt {{{\left( {5 - 2\sqrt 6 } \right)}^2}} - \sqrt {{{\left( {5 + 2\sqrt 6 } \right)}^2}} \\
= 5 - 2\sqrt 6 - \left( {5 + 2\sqrt 6 } \right)\\
= - 4\sqrt 6 \\
c)\sqrt {{{\left( {2 - \sqrt 3 } \right)}^2}} + \sqrt {{{\left( {1 - \sqrt 3 } \right)}^2}} \\
= 2 - \sqrt 3 + \sqrt 3 - 1\\
= 1\\
d)\sqrt {{{\left( {3 + \sqrt 2 } \right)}^2}} - \sqrt {{{\left( {1 - \sqrt 2 } \right)}^2}} \\
= 3 + \sqrt 2 - \left( {\sqrt 2 - 1} \right)\\
= 4\\
e)\sqrt {{{\left( {\sqrt 5 - \sqrt 2 } \right)}^2}} + \sqrt {{{\left( {\sqrt 5 + \sqrt 2 } \right)}^2}} \\
= \sqrt 5 - \sqrt 2 + \sqrt 5 + \sqrt 2 \\
= 2\sqrt 5 \\
f)\sqrt {{{\left( {\sqrt 2 + 1} \right)}^2}} - \sqrt {{{\left( {\sqrt 2 - 5} \right)}^2}} \\
= \sqrt 2 + 1 - \left( {5 - \sqrt 2 } \right)\\
= 2\sqrt 2 - 4
\end{array}$
