Đáp án:
\(100\)
Giải thích các bước giải:
d. \((13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}).230\dfrac{1}{25}+46.\dfrac{3}{4}\)
\(=[(13-2-10)+(\dfrac{1}{4}-\dfrac{5}{27}-\dfrac{5}{6})].230\dfrac{1}{25}+46.\dfrac{3}{4}\)
\(=(1-\dfrac{83}{108}).230\dfrac{1}{25}+46.\dfrac{3}{4}\)
\(=\dfrac{25}{108}.\dfrac{5751}{25}+46.\dfrac{3}{4}\)
\(=\dfrac{213}{4}+46.\dfrac{3}{4}\)
\(=53.\dfrac{1}{4}+46\dfrac{3}{4}\)
\(=(53+46)+(\dfrac{1}{4}+\dfrac{3}{4})\)
\(=99+1=100\)