cảm ơn trước nhe mn ^-^ (. là nhân nhé)

a)0,2.\(\dfrac{15}{36}\)-(\(\dfrac{2}{5}\)+\(\dfrac{2}{3}\)):1\(\dfrac{1}{5}\)

b)1\(\dfrac{13}{15}\).0,75-(\(\dfrac{8}{15}\)+0,25).\(\dfrac{24}{47}\)

c)5:(4\(\dfrac{3}{4}\)-1\(\dfrac{25}{28}\))-1\(\dfrac{3}{8}\):(\(\dfrac{3}{8}\)+\(\dfrac{9}{20}\))

a) 7/19.8/11+3/11.7/19+-12/19

b)-1,6 .-15/32+(0,8 - 2 4/25(hon so) ) : 3 2/3

các bạn giúp mình nhé mình đang cần gấp ạ

a.\(\dfrac{5}{-4}\).\(\dfrac{16}{25}\)+\(\dfrac{-5}{4}\).\(\dfrac{9}{25}\) (. là nhân nhé ạ ) e.\(11\dfrac{1}{4}\)-(\(2\dfrac{5}{7}\)+\(5\dfrac{1}{4}\))

b.\(4\dfrac{11}{23}\)-\(\dfrac{9}{14}\)+\(2\dfrac{12}{23}\)-\(\dfrac{5}{4}\) g.\(\dfrac{7}{19}\).\(\dfrac{8}{11}\)+\(\dfrac{7}{19}\).\(\dfrac{3}{11}\)+\(\dfrac{12}{19}\)

c.\(2\dfrac{13}{27}\)-\(\dfrac{7}{15}\)+\(3\dfrac{14}{27}\)-\(\dfrac{8}{15}\) h.\(-\left(\dfrac{1}{2}\right)^2\) .13\(\dfrac{9}{11}\)-25%.6\(\dfrac{2}{11}\)

d.\(\dfrac{-4}{9}\).\(\dfrac{7}{15}\)+\(\dfrac{4}{-9}\).\(\dfrac{8}{15}\) i.57%+1\(\dfrac{2}{15}\):\(\dfrac{68}{25}\)-2,82

Chung minh

\(A=\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{14}+-.+\dfrac{1}{20}\)\(< \dfrac{1}{2}\)

tính N = \(8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)

Tính

​\(A=2^2+4^2+6^2+...+98^2+100^2\)

Thực hiện phép tính

\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\)

Cho 3 điểm A,B,C thỏa mãn AB = BC = CA. Chứng tỏ rằng A,B,C là 3 đỉnh của một tam giác . Ai bt bài này thì giúp em vs

40%x - x - 1/8 = 3/4

\(\dfrac{3}{5.7}+\dfrac{3}{7.9}+-..+\dfrac{3}{59.61}\)

\(\left(x^2-4\right)\left(6-2x\right)=0\)

\(\dfrac{3}{2}-2x^2=-\dfrac{1}{2}\)

So sánh

\(A=\dfrac{10^{100}+1}{10^{101}+1}\)và\(B=\dfrac{10^{101}+1}{10^{102}+1}\)

530và12410

2711và818

536và1124

339 và 1121