a,
$n_{Cl_{2}}=\dfrac{m}{M}=\dfrac{71}{71}=1(mol)$
=> $V_{Cl_{2}}=n.22,4=1.22,4=22,4$ (lít)
b,
$n_{CO_{2}}=\dfrac{a}{N}=\dfrac{6.10^{23}}{6.10^{23}}=1(mol)$
=> $V_{CO_{2}}=n.22,4=1.22,4=22,4$ (lít)
c,
$V_{H_{2}O}=\dfrac{m}{D}=\dfrac{36}{1}=36(ml)=0,036$ (lít)
d,
$V_{C_{2}H_{6}O}=\dfrac{m}{D}=\dfrac{9,2}{0,8}=115(ml)=0,115$ (lít)