Đáp án:
Giải thích các bước giải:
$a,PTPƯ:4P+5O_2→2P_2O_5$
$n_{P}=\frac{46,5}{31}=1,5mol.$
$Theo$ $pt:$ $n_{O_2}=1,875mol.$
$⇒V_{O_2}=1,875.22,4=42l.$
$⇒V_{kk}=42.5=210l.$
$b,PTPƯ:C+O_2→CO_2$
$n_{C}=\frac{30}{12}=2,5mol.$
$Theo$ $pt:$ $n_{O_2}=n_{C}=2,5mol.$
$⇒V_{O_2}=2,5.22,4=56l.$
$⇒V_{kk}=56.5=280l.$
$c,PTPƯ:4Al+3O_2→2Al_2O_3$
$n_{Al}=\frac{67,5}{27}=2,5mol.$
$Theo$ $pt:$ $n_{O_2}=1,875mol.$
$⇒V_{O_2}=1,875.22,4=42l.$
$⇒V_{kk}=42.5=210l.$
$d,PTPƯ:2H_2+O_2→2H_2O$
$n_{H_2}=\frac{33,6}{22,4}=1,5mol.$
$Theo$ $pt:$ $n_{O_2}=0,75mol.$
$⇒V_{O_2}=0,75.22,4=16,8l.$
$⇒V_{kk}=16,8.5=84l.$
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