Lời giải:
Ta có:
(x+4)$\vdots$( x+4)
Lại có:
(x-5)$\vdots$( x+4)
=>x-5-(x+4)$\vdots$( x+4)
=>-9$\vdots$( x+4)
=>(x+4)∈Ư(-9)={-9;-3;-1;1;3;9}
•x+4=-9<=>x=-13
•x+4=-3<=>x=-7
•x+4=-1<=>x=-5
•x+4=1<=>x=-3
•x+4=3<=>x=-1
•x+4=9<=>x=5
Vậy x∈{-13;-7;-5;-3;-1;5}