Trong dd KOH 4%:
`m_(dd KOH)` = $V_1$ · 1.05 (g)
`m_(KOH)` = `(V_1 · 1.05 ·4%)/(100%)` = 0.042$V_1$ (g)
Trong dd KOH 10%:
`m_(dd KOH)` = $V_2$ · 1.12 (g)
`m_(KOH)` = `(V_2 · 1.12 · 10%)/(100%)` = 0.112$V_2$ (g)
Trong dd KOH 8%:
`m_(dd KOH) = 1500 · 1.1 = 1650 (g)
`m_(KOH)` = `(1650 · 8%)/(100%)` = 132 (g)
Ta có hệ pt:
$\left \{ {{1.05V_1 + 1.12V_2=1650} \atop {0.042V_1+0.112V_2=132}} \right.$
→ $\left \{ {{V_1=11000/21} \atop {V_2=6875/7}} \right.$