Đáp án:
\(\begin{array}{l}
a)\\
{C_{{M_{{H_2}S{O_4}}}}} = 1,5M\\
b)\\
{C_{{M_{N{a_2}S{O_4}}}}} = 0,6M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{H_2}S{O_4} + 2NaOH \to N{a_2}S{O_4} + 2{H_2}O\\
{n_{NaOH}} = {C_M} \times V = 0,3 \times 2 = 0,6mol\\
{n_{{H_2}S{O_4}}} = \dfrac{{{n_{NaOH}}}}{2} = 0,3mol\\
{C_{{M_{{H_2}S{O_4}}}}} = \dfrac{n}{V} = \dfrac{{0,3}}{{0,2}} = 1,5M\\
b)\\
{n_{N{a_2}S{O_4}}} = \dfrac{{{n_{NaOH}}}}{2} = \frac{{0,6}}{3} = 0,3mol\\
{C_{{M_{N{a_2}S{O_4}}}}} = \dfrac{n}{V} = \dfrac{{0,3}}{{0,2 + 0,3}} = 0,6M
\end{array}\)