Đáp án:
V= 3211,47\({m^3}\)
Giải thích các bước giải:
Sơ đồ:
\(4C{H_4}\xrightarrow{{}}2{C_2}{H_2}\xrightarrow{{}}{C_4}{H_4}\xrightarrow{{}}{C_4}{H_6}\xrightarrow{{}}{({C_4}{H_6})_n}\)
Ta có:
\({n_{{C_4}{H_6}}} = \frac{1}{{12.4 + 6}} = \frac{1}{{54}} \to {n_{C{H_4}{\text{ lý thuyết}}}} = 4{n_{{C_4}{H_6}}} = \frac{1}{{54}}.4 = \frac{2}{{27}} \to {n_{C{H_4}{\text{ thực tế}}}} = \frac{2}{{27.55\% }} = \frac{{40}}{{279}} \to {V_{C{H_4}}} = \frac{{40}}{{279}}.1000.22,4 = 3211,47{\text{ }}{{\text{m}}^3}\)