Bài 2:
Gọi CTPT cần tìm :$C_xH_y$
$n_{CO_2} = \dfrac{19,8}{44} = 0,45 (mol)$
$n_{H_2O} = 0,6 (mol)$
$C_2H_4 + O_2 \xrightarrow{{t°}} xCO_2 + yH_2O$
Mà $\dfrac{x}{y} = \dfrac{n_{CO_2}}{2n_{H_2O}} = \dfrac{3}{8}$
$\to C_3H_8$
b,
$CH_3-CH_2-CH_3$
Bài 3:
$n_{O_2} = 1,9 (mol)$
$C_nH_{2n+2} + \dfrac{3n+1}{2} O_2 \xrightarrow{{t°}} nCO_2 + (n+1)H_2O$
$\Rightarrow 17,2:\Big(\dfrac{1,9}{\dfrac{3n+1}{2}}\Big) = 14n+2$
$\Rightarrow n = 6$
$\to C_6H_{14}$
* tác dụng với $Cl_2(a/s)$
$C_6H_{14} + Cl_2 \xrightarrow[-HCl]{{a/s}} C_6H_{13}Cl + CH_3C(Cl)CH_2CH_2CH_3$
