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ducmanhpro2008
2 năm trước
Từ một khí cầu đang bay lên cao theo phương thẳng đứng với vận tốc không đổi bằng 5m/s, người ta thả nhẹ nhàng một vật nặng. Hỏi sau 2s, vật cách khí cầu bao xa? Tính chiều dài tổng cộng đường đi của vật trong 2s đó. Biết khi thả vật vận tốc khí cầu không đổi. Lấy g=10m/s2
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