a),b) Vì AD là phân giác $BAC$
⇒ $BAD=DAC=\dfrac{1}{2}BAC$
$BAD=DAC=\dfrac{1}{2}.60^o$
⇒ $BAD=DAC=30^o$
c) Vì $DM//AB$
⇒ $BAD=ADM=30^o$ (so le trong)
d) Vì $MK//AD$
⇒ $ADM=DMK=30^o$ (so le trong)
e) Vì $MK//AD$
⇒ $DAM=CMK=30^o$ (đồng vị)
Xét tam giác ABC có AD là phân giác:
=>gócBAD=gocsDAM=gócBAC/2=60/2=30
Ta có AB//DM
=>gócBAD=gócADM=30(2goc so le trong)
Ta có:AD//MK
=>gócADM=gocsDMK=30(2 góc SLT);
góc DAC = góc KMC(2 góc đồng vị)
Giúp mik bài 16,17,8A,8B. Nhanh nhé mik đang cần gấp. Thanks
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đề bài là tìm x ạ giúp em với,thanks $\frac{2x+2\sqrt[]{x}+2 }{\sqrt[]{x}}$ = 8
Tổng kết thi đua 100 điểm 10 dâng tặng cô , lớp 6A có 43 bạn được từ 1 điểm 10 trở lên , 39 bạn đạt từ 3 điểm 10 trở lên , 5 bạn đạt 4 điểm 10 trở lên không có ai được trên 4 điểm 10 trở lên . Tính xem trong đợt thi đua đó , lớp 6A có bao nhiêu điểm 10 ? Giúp tao nha chiều mai tao đi học rồi
Có bạn nào chuyên toán giúp mik được ko ạ
cho tứ giác abcd các phân giác trong cắt nhau tại m,n,p,q chứng minh tứ giác mnpq có hai góc đối bù nhau
Giải phương trình $1/$ $x^{4}$ - $4x^{3}$ +$8x^{2}$ + $6x$ - $9$ = $0$ $2/$ $x^{2}$ - $|x|$ - $2$ = $0$
Tìm GTNN của : $B = \frac{20}{21-/x-2/}$
Lm cách nào để học ko bị nhàm chân
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