Em tham khảo nha :
\(\begin{array}{l}
VD2:\\
a)\\
{n_{HCl}} = {C_M} \times V = 2 \times 0,5 = 1mol\\
b)\\
{n_{ZnC{l_2}}} = {C_M} \times V = 0,25 \times 0,1 = 0,025mol\\
VD3:\\
a)\\
{V_{Ca{{(OH)}_2}}} = \dfrac{n}{{{C_M}}} = \dfrac{{0,3}}{2} = 0,15l\\
b)\\
{n_{{H_2}S{O_4}}} = \dfrac{m}{M} = \dfrac{{49}}{{98}} = 0,5mol\\
{V_{{H_2}S{O_4}}} = \dfrac{n}{{{C_M}}} = \dfrac{{0,5}}{{0,5}} = 1l
\end{array}\)