Đáp án:
$\begin{array}{l}
{\left( { - 4 + 2y} \right)^3} = {2^3}{\left( {y - 2} \right)^3}\\
= 8\left( {C_3^0.{y^3}.{{\left( { - 2} \right)}^0} + C_3^1.{y^2}.{{\left( { - 2} \right)}^1} + C_3^2.y.{{\left( { - 2} \right)}^2} + C_3^3.{y^0}.{{\left( { - 2} \right)}^3}} \right)\\
= 8\left( {{y^3} - 6{y^2} + 12y - 8} \right)\\
= 8{y^3} - 48{y^2} + 96y - 64
\end{array}$
