Đáp án:
Bạn tham khảo lời giải ở dưới nhé!!!
Giải thích các bước giải:
a,
\(\begin{array}{l}
{C_{12}}{H_{22}}{O_{11}} + Ca{(OH)_2} \to {C_{12}}{H_{22}}{O_{11}}.CaO.{H_2}O\\
{C_{12}}{H_{22}}{O_{11}}.CaO.{H_2}O + C{O_2} \to {C_{12}}{H_{22}}{O_{11}} + CaC{O_3} + {H_2}O\\
{C_{12}}{H_{22}}{O_{11}} + {H_2}O \to {C_6}{H_{12}}{O_6} + {C_6}{H_{12}}{O_6}\\
{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}\\
{C_6}{H_{12}}{O_6} + {O_2} \to C{H_3}COOH + {H_2}O\\
C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O\\
C{H_3}COONa + NaOH \to C{H_4} + N{a_2}C{O_3}\\
C{H_4} + {O_2} \to HCHO + {H_2}O
\end{array}\)
b,
\(\begin{array}{l}
{( - {C_6}{H_{10}}{O_5} - )_n} + n{H_2}O \to n{C_6}{H_{12}}{O_6}\\
{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}\\
{C_2}{H_5}OH \to {C_2}{H_4} + {H_2}O\\
3{C_2}{H_4} + 2KMn{O_4} + 4{H_2}O \to 3{C_2}{H_4}{(OH)_2} + 2KOH + 2Mn{O_2}
\end{array}\)
