\(y = \sqrt {7 + 5{{\cot }^4}{x^4}} \)
A.\(\frac{{20{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
B.\(\frac{{ - 20{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
C.\(\frac{{ - 10{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
D.\(\frac{{10{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
A.\(\frac{{20{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
B.\(\frac{{ - 20{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
C.\(\frac{{ - 10{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
D.\(\frac{{10{x^3}{{\cot }^3}{x^4}}}{{{{\sin }^2}{x^4}\sqrt {7 + 5{{\cot }^4}{x^4}} }}\)
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Hóa Học lớp 12
