Tham khảo
` \frac{1}{2}.(x-\frac{2}{3})-\frac{1}{3}.(2x-3)=x+\frac{1}{2}`
`⇒\frac{1}{2}x-\frac{1}{3}-\frac{2}{3}x+1=x+\frac{1}{2}`
`⇒-\frac{1}{6}x+\frac{2}{3}-\frac{1}{2}=x`
`⇒\frac{2}{3}-\frac{1}{2}=x+\frac{1}{6}x`
`⇒\frac{1}{6}=\frac{7}{6}x`
`⇒x=\frac{1}{6}:\frac{7}{6}`
`⇒x=\frac{1}{7}`
`\text{©CBT}`