$x - \dfrac{1}{9} = \dfrac{8}{5}$
$x = \dfrac{8}{5} + \dfrac{1}{9}$
$x = \dfrac{77}{45}$
Vậy $x = \dfrac{77}{45}$
$x + 3\dfrac{1}{2} + x = 24\dfrac{1}{4}$
$2 \times x + \dfrac{7}{2} = \dfrac{97}{4}$
$2 \times x = \dfrac{83}{4}$
$x = \dfrac{83}{4} \times \dfrac{1}{2}$
$x = \dfrac{83}{8}$
Vậy $x = \dfrac{83}{8}$