Đáp án:
Giải thích các bước giải:
1) `2x^2+5x+3=0`
Nhẩm nghiệm ta có:
`a-b+c=2-5+3=0`
`⇒ x_{1}=-1,x_{2}=- 3/2`
Vậy `S={-1;- 3/2}`
2) \(\left\{\begin{array}{l}-x+3 y=5 \\ x+y=-1\end{array}\right.\)
`⇔` \(\left\{\begin{array}{l}-x+3 y=5 \\ 3x+3y=-3\end{array}\right.\)
`⇔` \(\left\{\begin{array}{l}-4x=8 \\ x+y=-1\end{array}\right.\)
`⇔` \(\left\{\begin{array}{l}x=-2 \\ -2+y=-1\end{array}\right.\)
`⇔` \(\left\{\begin{array}{l}x=-2 \\y=1\end{array}\right.\)
Vậy `(x,y)=(-2;1)`