Giải thích các bước giải:
1.$4x(x-1)=|2x-1|+1$
$\rightarrow 4x^2-4x+1=|2x-1|+2$
$\rightarrow (2x-1)^2-|2x-1|-2=0$
$\rightarrow |2x-1|^2-|2x-1|-2=0$
$\rightarrow (|2x-1|-2)(|2x-1|+1)=0$
$\rightarrow |2x-1|=2$
$\rightarrow 2x-1=2\rightarrow x=\dfrac{3}{2}$
Hoặc $2x-1=-2\rightarrow x=\dfrac{-1}{2}$