Đáp án: \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\)
Giải thích các bước giải:
3 . $(2x-3)^{2}$ = 48
→ $(2x-3)^{2}$ = 16
→ \(\left[ \begin{array}{l}(2x-3)^2=4^2\\(2x-3)^2=-4^2\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x-3=4\\2x-3=-4\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x=7\\2x=-1\end{array} \right.\)
→ \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\)
