Đáp án:
0,08mol{HCOOC6H5;COOCH3+{NaOH:0,08mol;KOH:0,04mol
Gọi {HCOOC6H5:xmol;HCOOCH3:ymol
nOH−=0,08+0,04=0,12
HCOOC6H5+2OH− →HCOO- +C6H5O- +H2O
HCOOCH3+OH− →HCOO− +CH3OH
=> {x+y=0,082;x+y=0,12=>{x=0,04;y=0,04
[(0,04.122)/(0,04.122+0,04.74)].100%=62,24%