a,`PTHH: Fe+2HCl→FeCl_2+H_2↑`
b,Ta có: `n_(Fe)=m/M=(11,2)/56=0,2`
Theo `PTHH`,ta thấy: `n_(HCl)=2.n_(Fe)=2.0,2=0,4`(mol)
`⇒m_(HCl)=n.M=0,4.(35,5+1)=14,6`(g)
c,Theo `PTHH`,ta thấy: `n_(H_2)=n_(Fe)=0,2`(mol)
`⇒V_(H_2)=n.22,4=0,2.22,4=4,48`(l)
Xin hay nhất =_=