n C2H4 = 0,56/22,4=0,025(mol)
PTHH:C2H4+Br2->C2H4Br2
(mol)__0,025__0,025__0,025
m C2H4Br2 = 0,025.188=4,7(g)
V Br2 = 0,025/1 = 0,025(l) = 25(ml)
PTHH: C2H4 + 3O2 -to-> 2CO2 + 2H2O
(mol)___0,025_____________0,05___________
PTHH: Ba(OH)2+CO2->BaCO3+H2O
(mol)___0,05_____0,05______0,05________
m BaCO3 = m kt = 0,05.197=9,85(g)