Theo dãy hđhh thì Cu không pứ với H2SO4 loãng
m Cu = 6,4(g) => n Cu =0,1(mol)
n H2 = 0,2/2=0,1(mol)
PTHH:Zn+H2SO4->ZnSO4+H2
(mol)__0,1___0,1______0,1____0,1__
m Zn = 0,1.65=6,5(g)
m = 6,5+6,4=12,9(g)
PTHH:Cu+2H2SO4(đ)-to->CuSO4+2H2O+SO2
(mol)__0,1____________________________________0,1_
V = 22,4.0,1=2,24(l)