$n_{Fe}=25,2/56=0,45mol$
$a/3Fe+2O_2\overset{t^o}\to Fe_3O_4$
b/Theo pt :
$n_{O_2}=2/3.n_{Fe}=2/3.0,45=0,3mol$
$⇒V_{O_2}=0,3.22,4=6,72l$
$c/2KMnO_4\overset{t^o}\to K_2MnO_4+MnO_2+O_2$
Theo pt :
$n_{KMnO_4}=2.n_{O_2}=2.0,3=0,6mol$
$⇒m_{KMnO_4}=0,6.158=94,8g$