Đáp án:
$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x+7 \right )\left ( x-1 \right )$
Giải thích các bước giải:
$\left ( 12x-1 \right )\left ( 6x-1 \right )\left ( 4x-1 \right )\left ( 3x-1 \right )-330$
$= \left [ \left ( 12x-1 \right )\left ( 3x-1 \right ) \right ]\left [ \left ( 6x-1 \right )\left ( 4x-1 \right ) \right ]-330$
$= \left ( 36x^{2}-15x+1 \right )\left ( 24x^{2}-10x+1 \right )-330$
$= \left [ 3\left ( 12x^{2}-5x \right )+ 1\right ]\left [ 2\left ( 12x^{2}-5x \right )+1 \right ]-330$
$= 6\left ( 12x^{2}-5x \right )+5\left ( 12x^{2}-5x \right )-329$
$= \left [ 6\left ( 12x^{2}-5x \right )+47 \right ]\left ( 12x^{2}-5x-7 \right )$
$= \left [ 6\left ( 12x^{2}-5x+47 \right ) \right ]\left ( 12x+7 \right )\left ( x-1 \right )$