Giả sử I(x;y;z). I cách đều A, B, C, D hay IA = IB = IC = ID \(\left\{\begin{matrix} (x-1)^2+y^z^2=x^2+(y+2)^2+z^2\\ (x-1)^2+y^z^2=x^2+y^2+(z-3)^2\\ (x-1)^2+y^z^2=(x-1)^2+(y+2)^2+(z-3)^2 \end{matrix}\right.\)| \(\Leftrightarrow \left\{\begin{matrix} 2x+4y=-3\\ -6z=-8\\ 4y-6z=-13 \end{matrix}\right.\)