Đáp án:
Giải thích các bước giải:
`a,(5x-1)/6+x=(6-x)/4`
`=>2(5x-1)+12x=3(6-x)`
`=>10x-2+12x-18+3x=0`
`=>25x-20=0`
`=>25x=20`
`=>x=4/5`
`b,x/[2(x+3)]-x/(2-2x)=(2x)/[(1-x)(x+3)]ĐKXĐ:x\ne1;-3`
`=>x/[2(x+3)]+x/[2(x-1)]=-(2x)/[(x-1)(x+3)]`
`<=>[x(x-1)]/[2(x+3)(x-1)]+[x(x+3)]/[2(x+3)(x-1)]=-(4x)/[2(x-1)(x+3)]`
`<=>x(x-1)+x(x+3)=4x`
`<=>x^2-x+x^2+3x-4x=0`
`<=>2x^2-2x=0`
`<=>2x(x-1)=0`
$⇒\left[ \begin{array}{l}x=0(TM)\\x=1(Loại)\end{array} \right.$
