Câu 1.
$n_{SO2}=\dfrac{1,12}{22,4}= 0,05(mol)$
$n_{NaOH}=1.0,05=0,05(mol)$
$T=\dfrac{n_{NaOH}}{n_{SO_2}}=1$
Vậy, X là $NaHSO_3$
Câu 2.
$n_{SO2}=\dfrac{3,36}{22,4}= 0,15(mol)$
$n_{NaOH}=1.0,1=0,1(mol)$
$T=\dfrac{n_{NaOH}}{n_{SO_2}}=0,67$
Vậy, A chứa muối $NaHSO_3$