$n_{C_2H_5OH}=2,3/46=0,05mol$
$PTHH :$
$C_2H_5OH+3O_2\overset{t^o}\to 2CO_2↑+3H_2O$
a/Theo pt :
$n_{CO_2}=2.n_{C_2H_5OH}=2.0,05=0,1mol$
$⇒V_{CO_2}=0,1.22,4=2,24l$
b/Theo pt :
$n_{O_2}=3/2.n_{C_2H_5OH}=3/2.0,05=0,075mol$
$⇒V_{kk}=0,075.22,4.5=8,4l$
$c/CO_2+Na→Na_2O+C4
Theo pt :
$n_C=n_{CO_2}=0,1mol⇒V_C=0,1.12=1,2l$