Đáp án:
60,26%
Giải thích các bước giải:
\(\begin{array}{l}
2{C_6}{H_5}OH + 2Na \to 2{C_6}{H_5}ONa + {H_2}\\
2{C_2}{H_5}OH + 2Na \to 2{C_2}{H_5}ONa + {H_2}\\
2Na + 2{H_2}O \to 2NaOH + {H_2}\\
{C_6}{H_5}OH + NaOH \to {C_6}{H_5}ONa + {H_2}O\\
hh:{C_6}{H_5}OH(a\,mol),{C_2}{H_5}OH(b\,mol),{H_2}O(c\,mol)\\
n{H_2} = \dfrac{{11,2}}{{22,4}} = 0,5\,mol\\
nNaOH = 0,2 \times 2 = 0,4\,mol\\
94a + 46b + 18c = 62,4\\
a + b + c = 0,5 \times 2\\
a = 0,4\\
\Rightarrow a = 0,4;b = 0,5;c = 0,1\\
C\% {C_6}{H_5}OH = \dfrac{{0,4 \times 94}}{{62,4}} \times 100\% = 60,26\%
\end{array}\)