Giải thích các bước giải:
\(\begin{array}{l}
{X_2}C{O_3} + 2HCl \to 2XCl + C{O_2} + {H_2}O\\
{X_2}S{O_3} + 2HCl \to 2XCl + S{O_2} + {H_2}O\\
C{O_2} + NaOH \to NaHC{O_3}\\
S{O_2} + NaOH \to NaHS{O_3}\\
{n_{NaOH}} = 1,5mol\\
\to {n_{hỗnhợp}} = {n_{khí}} = {n_{NaOH}} = 1,5mol\\
\to {M_{hỗnhợp}} = \dfrac{{165}}{{1,5}} = 110\\
\to {M_{{X_2}C{O_3}}} < 110 < {M_{{X_2}S{O_3}}}\\
\to X \times 2 + 12 + 16 \times 3 < 110 < X \times 2 + 32 + 16 \times 3\\
\to 25 > X > 15\\
\to X = 23(Na)
\end{array}\)