Đáp án:
C3H8O
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
nC{O_2} = \dfrac{m}{M} = \dfrac{{6,6}}{{44}} = 0,15\,mol\\
nC = nC{O_2} = 0,15\,mol\\
n{H_2}O = \dfrac{m}{M} = \dfrac{{3,6}}{{18}} = 0,2\,mol\\
nH = 2n{H_2}O = 0,4\,mol\\
mO = 3 - 0,15 \times 12 - 0,4 = 0,8g\\
nO = \frac{m}{M} = \dfrac{{0,8}}{{16}} = 0,05\,mol\\
nC:nH:nO = 0,15:0,4:0,05 = 3:8:1\\
\Rightarrow CTDGN:{C_3}{H_8}O\\
MA = 60g/mol \Rightarrow 60n = 60 \Rightarrow n = 1\\
CTPT:{C_3}{H_8}O\\
b)\\
C{H_3} - C{H_2} - C{H_2} - OH\\
c)\\
2{C_3}{H_7}OH + 2Na \to 2{C_3}{H_7}ONa + {H_2}
\end{array}\)
