$CTTQ:C_nH_{2n+1}OH$
`n_{CO_2}=4,48:22,4=0,2(mol)`
`n_{H_2O}=5,4:18=0,3(mol)`
`n_{ancol}=n_{H_2O}-n_{CO_2}=0,3-0,2=0,1(mol)`
$PTHH:C_nH_{2n+1}OH+\frac{3n}{2}O_2\xrightarrow{t^o}nCO_2+(n+1)H_2O$
`pt:---1---------n--`
`pứ: ---0,1-------0,2--`
Áp dụng ĐLTL:
$\frac{1}{0,1}=\frac{n}{0,2}$
`⇒n=2`
`→CTHH: C_2H_5OH`