Đáp án:
3,758125g
Giải thích các bước giải:
\(\begin{array}{l}
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
{C_2}{H_2} + 2B{r_2} \to {C_2}{H_2}B{r_4}\\
{C_2}{H_2} + 2AgN{O_3} + 2N{H_3} \to A{g_2}{C_2} + 2N{H_4}N{O_3}\\
nA{g_2}{C_2} = \dfrac{{11,025}}{{240}} = 0,0459375\,mol\\
n{C_2}{H_2} = nA{g_2}{C_2} = 0,0459375\,mol\\
\% VC{H_4} = \dfrac{{1,4}}{{4,48}} \times 100\% = 31,25\% \\
\% V{C_2}{H_2} = \dfrac{{0,0459375 \times 22,4}}{{4,48}} \times 100\% = 22,96875\% \\
\% V{C_2}{H_4} = 100 - 31,25 - 22,96875 = 45,78125\% \\
n{C_2}{H_4} = 0,2 - 0,0459375 - 0,0625 = 0,0915625\,mol\\
m = 0,0915625 \times 28 + 0,0459375 \times 26 = 3,758125g
\end{array}\)
