$\left \{ {{2x-y=3} \atop {x+2y=4}} \right.$
$⇒$ $\left \{ {{y=2x-3} \atop {x+2y=4}} \right.$
$⇔$ $\left \{ {{y=2x-3} \atop {x+2.(2x-3)=4}} \right.$
$⇔$ $\left \{ {{y=2x-3} \atop {x+4x - 6 = 4}} \right.$
$⇔$ $\left \{ {{y=2x-3} \atop {5x=10}} \right.$
$⇔$ $\left \{ {{y=2x-3} \atop {x=2}} \right.$
$⇔$ $\left \{ {{y=1} \atop {x=2}} \right.$
Vậy `(x;y)=(2;1)`.