Đáp án:
x=0
Giải thích các bước giải:
\(\begin{array}{l}
\left| {x + 1} \right| - \left| {2x + 3} \right| = - x + 2\\
\to \left[ \begin{array}{l}
x + 1 - 2x - 3 = - x + 2\left( {DK:x \ge - 1} \right)\\
- x - 1 + 2x + 3 = - x + 2\left( {DK:x < - \dfrac{3}{2}} \right)\\
- x - 1 - 2x + 3 = - x + 2\left( {DK: - 1 > x \ge - \dfrac{3}{2}} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
- 2 = 2\left( {vô lý} \right)\\
2x = 0\\
- 2x = 0
\end{array} \right.\\
\to x = 0\left( {TM} \right)
\end{array}\)
