$\text{Có: Q = $\dfrac{x+1}{2x}$ (x $\neq$ 0; x $\neq$ ± 2)}$
`Q = \frac{x+1}{2x} = 1/2 + 1/2x`
$\text{Để Q nguyên ⇔ 2x ∈ Ư(1) = {±1}}$
`⇔` \(\left[ \begin{array}{l}2x=1\\2x=-1\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=\dfrac{1}{2}(TM)\\x=\dfrac{-1}{2}(TM)\end{array} \right.\)
$\text{Vậy để Q nguyên thì x = ± $\dfrac{1}{2}$}$