a) PTHH: H2+ZnO→Zn+H2O
b) nZnO=12,15 : 81=0,15 (mol)
Theo PTHH: nZn=nZnO=0,15 (mol)
→mZn=0,15.65=9,75 (g)
c) PTHH: Zn+2HCl→ZnCl2+H2
nHCl=20 : 35,5=0,56 (mol)
Xét tỉ lệ:
0,15/1<0,56/2 →Sau pư HCl dư
Theo PTHH: nZnCl2=nZn=0,15 (mol)
→mZnCl2=0,15.136=20,4 (g)